document.write( "Question 833742: Given the angle, find the reference angle:
\n" ); document.write( " a. theta= 970
\n" ); document.write( "b. theta= -120\r
\n" ); document.write( "\n" ); document.write( "Calculate:
\n" ); document.write( "a. sin(13pi/6)
\n" ); document.write( "b. cos(-5pi/3)
\n" ); document.write( "c. tan(970)
\n" ); document.write( "d. csc(-120)
\n" ); document.write( "e. cot(-5pi/3)\r
\n" ); document.write( "\n" ); document.write( "Thank you!! \n" ); document.write( "
Algebra.Com's Answer #502724 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Given the angle, find the reference angle:
\n" ); document.write( "a. theta= 970
\n" ); document.write( "=70˚(in quadrant III)
\n" ); document.write( "..
\n" ); document.write( "b. theta= -120
\n" ); document.write( "=60˚(in quadrant III)
\n" ); document.write( "..
\n" ); document.write( "Calculate:
\n" ); document.write( "a. sin(13pi/6)
\n" ); document.write( "=sin(π/6)=1/2(in quadrant I)
\n" ); document.write( "..
\n" ); document.write( "b. cos(-5pi/3)
\n" ); document.write( "=cos(2π/3)=1/2 (in quadrant I)
\n" ); document.write( "..
\n" ); document.write( "c. tan(970˚)
\n" ); document.write( "=tan(70˚)≈-2.7475 (in quadrant III)
\n" ); document.write( "..
\n" ); document.write( "d. csc(-120)
\n" ); document.write( "csc(60˚)=-2/√3=-2√3/2(in quadrant III)
\n" ); document.write( "..
\n" ); document.write( "e. cot(-5pi/3)
\n" ); document.write( "=cot(2π/3)=1/√3=√3/3(in quadrant I) \n" ); document.write( "
\n" );