document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=833708>Question 833708</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular cornfield is 144 feet. The length of the field is 12 <BR>\n" );
document.write( "feet more than the width. What is the area, in square feet, of the cornfield? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502709 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502709\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x for width<BR>\n" );
document.write( "y for length\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=x%2B12 ALIGN=MIDDLE  ALT=\"y=x%2B12\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B2y=144 ALIGN=MIDDLE  ALT=\"2x%2B2y=144\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  You want x and y and will use them to get area, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=xy ALIGN=MIDDLE  ALT=\"xy\"   DISABLED_style= \"max-width:90%; height:auto;\" >;  simple substitution for y is the way to go. </SPAN>\n" );
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