document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=833623>Question 833623</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me? The width of a rectangle is two meters more than one-third the length of the rectangle. If the perimeter of the rectangle is 50 meters, find the width and length. You can leave the final as a fraction.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502705 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502705\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x and y width and length\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%281%2F3%29y%2B2 ALIGN=MIDDLE  ALT=\"x=%281%2F3%29y%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" >; <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B2y=50 ALIGN=MIDDLE  ALT=\"2x%2B2y=50\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Try substitution for x. </SPAN>\n" );
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