document.write( "Question 70500: Find the legs of an isosolese triangle if the perimeter is 32 and the altitude to the base is 8. \n" ); document.write( "
Algebra.Com's Answer #50268 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
2X+Y=32
\n" ); document.write( "Y=32-2X
\n" ); document.write( "THE EQUAL SIDES ARE X AND THE BASE IS Y
\n" ); document.write( "THEREFORE A TRIANGLE IS FORMED BY 1/2 BASE (32-2X)/2 AND THE OTHER SIDE IS THE ALTITUDE OF 8.
\n" ); document.write( "THEREFORE WE HAVE A TRIANGLE WITH SIDES 8, (32-2X)/2 & X.
\n" ); document.write( "USING THE PATAGOREAN THEROM OF A^2+B^2=C^2
\n" ); document.write( "8^2+(32-2X)/2)^2=X^2
\n" ); document.write( "64+(16-X)^2=X^2
\n" ); document.write( "64+256-32X+X^2=X^2 CANCELLING OUT THE X^2 WE GET
\n" ); document.write( "-32X=-256-64
\n" ); document.write( "-32X=-320
\n" ); document.write( "X=-320/-32
\n" ); document.write( "X=10 FOR THE TWO EQUAL LEGS THUS
\n" ); document.write( "2X+Y=32
\n" ); document.write( "2*10+Y=32
\n" ); document.write( "Y=32-20
\n" ); document.write( "Y=12 FOR THE BASE \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );