document.write( "Question 70489: An airplane took 2.5 hours to fly 625 miles with the wind. It took 4 hours and 10 minutes to make the return trip, against the same wind. Find the wind speed and the speed of the plane in still air. \r
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document.write( "Against a head wind, Jeff computes his flight time for a trip of 2,900 miles at 5 hours. The flight would take 4 hours and 50 minutes if the head wind was half as much. Find the head wind and the planes air speed.\r
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document.write( "In 1927 Charles Lindburg flew the Spirit of St. Louis from NYC to Paris at an average speed of 107.4mi/h. 11 years later, Howard Hughes flew the same route, averaged 217.1 mil/h, and took 16 hours and 57 minutes less time. Find the length of their route.\r
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Algebra.Com's Answer #50266 by piglet162431(90)![]() ![]() ![]() You can put this solution on YOUR website! let statements: \n" ); document.write( "let x be the be speed of the plane in still air. \n" ); document.write( "Let y be the speed of the wind. \n" ); document.write( "since d=rt, we can come upwith a system of equations. \n" ); document.write( "625=2.5(x+y) \n" ); document.write( "625=4 1/6(x-y) \n" ); document.write( "The first equation could be simplied into 250=x+y. \n" ); document.write( "the second equation, multiply both sides to the reciprocal of 4 1/6, which is 6/25: \n" ); document.write( "150=x-y \n" ); document.write( "now, line them up, and use addition method. \n" ); document.write( "x-y=150 \n" ); document.write( "x+y=250 \n" ); document.write( "2x=400 \n" ); document.write( "x=200 \n" ); document.write( "Plug this value back for y. 200-y=150, y=50. \n" ); document.write( "The speed of the plane in still is 200 m/h, whhile the speed of the wind is 50 m/h. \n" ); document.write( " \n" ); document.write( " |