document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=833460>Question 833460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the area of a rectangle whose leanrh is twice the breadth and permeter is 30 cm.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502647 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502647\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2length + 2width [\"breadth'}<BR>\n" );
document.write( "P = 30<BR>\n" );
document.write( "L = 2W<BR>\n" );
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document.write( "Substitute the values<BR>\n" );
document.write( "30 = 2(2W) + 2W<BR>\n" );
document.write( "30 = 4W + 2W<BR>\n" );
document.write( "30 = 6W<BR>\n" );
document.write( "divide by 6<BR>\n" );
document.write( "W = 5<BR>\n" );
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document.write( "If W=5, what is L? </SPAN>\n" );
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