document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=833526>Question 833526</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find two numbers whose sum is 64 if one of the numbers is 1/7 the other.  I put x plus 1 over 7 x equals 64.   My mom checked the answer book and the correct answers are 8 and 56. The explanation is showing to multiply7 times X instead of dividing by 7.. We are confused.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502618 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two ways<BR>\n" );
document.write( "64=y+y/7<BR>\n" );
document.write( "y will be the larger <BR>\n" );
document.write( "y=56<BR>\n" );
document.write( "64=7x+x<BR>\n" );
document.write( "x will be the smaller<BR>\n" );
document.write( "x=8\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );