document.write( "Question 833510: Five lines parallel to the base of a triangle divide the other sides of the triangle each into 6 equal segments and the area into 6 distinct parts. If the area of the largest of these parts is 66 cm squared then the area of the original triangle is:\r
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document.write( "I have drawn this out and played around with the lines but I do not see how I can find the area of any of the 6 sections \n" );
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Algebra.Com's Answer #502614 by KMST(5328)![]() ![]() You can put this solution on YOUR website! Each section plus everything above that section base is a triangle. \n" ); document.write( "They are all similar triangles with the side lengths in the proportion \n" ); document.write( " \n" ); document.write( "The length of base and height are also in the same proportion, of course. \n" ); document.write( "So, the areas are in the proportion \n" ); document.write( " \n" ); document.write( "The area of the triangle made up of the top two sections is \n" ); document.write( "The area of the triangle made up of the top three sections is \n" ); document.write( "The area of the triangle made up of the top four sections is \n" ); document.write( "The area of the triangle made up of the top five sections is \n" ); document.write( "The original triangle's area is \n" ); document.write( "Let's call the area of the smallest (top) triangle \n" ); document.write( "The area of the triangle made up of the top five sections is \n" ); document.write( "The original triangle's area is \n" ); document.write( "The difference, \n" ); document.write( "Our equation is \n" ); document.write( "The area of the original triangle is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "A picture is worth a thousand words: \n" ); document.write( " \n" ); document.write( "Do you see hoe there are |