document.write( "Question 833483: I'm in need of help very badly I have read and reread the assignment looked at the example.And I still don't understand I talked to my professor done what she said to do and nope it's a lost cause i'm starting to think , I have used tutors
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document.write( "but we are only allowed so many hours. here's the question.
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document.write( " 6
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document.write( " 7
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document.write( "+
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document.write( "3 3
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document.write( " 7
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Algebra.Com's Answer #502565 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Do you mean 6/7 + 3 3/7 ? \n" ); document.write( "The denominators are the same, you can add \n" ); document.write( "= 3 3/7 is 3 + 3/7 \n" ); document.write( "----- \n" ); document.write( "6/7 + 3 + 3/7 = 3 + 9/7 \n" ); document.write( "9/7 = 7/7 + 2/7 = 1 + 2/7 \n" ); document.write( "--- \n" ); document.write( "3 + 1 + 2/7 = 4 + 2/7 \n" ); document.write( "or 4 2/7 \n" ); document.write( "-------------- \n" ); document.write( "Enter fractions as I did, not as you did. \n" ); document.write( " |