document.write( "Question 833437: The first plane has 117 more seats than the 2nd plane. The third plane has 18 fewer seats than the the second plane. The total number of seats is 405.Find the the number of seats for each plane. \n" ); document.write( "
Algebra.Com's Answer #502538 by JulietG(1812)\"\" \"About 
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A + B + C = 405
\n" ); document.write( "A = B + 117 (The first plane has 117 more seats than the 2nd plane.)
\n" ); document.write( "C = B - 18 (The third plane has 18 fewer seats than the the second plane.)
\n" ); document.write( "Go back to the first equation, but substitute the values
\n" ); document.write( "(B+117) + B + (B-18) = 405
\n" ); document.write( "Add the Bs
\n" ); document.write( "3B +117 -18 = 405
\n" ); document.write( "3B +99 = 405
\n" ); document.write( "Subtract 99 from each side
\n" ); document.write( "3B = 306
\n" ); document.write( "Divide each side by 3
\n" ); document.write( "B = 102
\n" ); document.write( "If the second plane has 102 seats, you should be able to figure out the first and third planes :-)
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