document.write( "Question 833439: In a bicycle race over a 20 km route, Danny finished 8 minutes ahead of John. Danny pedaled 5 km per hour faster than John. What was Danny's rate \n" ); document.write( "
Algebra.Com's Answer #502536 by josgarithmetic(39627)\"\" \"About 
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Uniform rates for travel, using \"R%2AT=D\".
\n" ); document.write( "This example is in kilometers and hours.
\n" ); document.write( "8 minutes is \"8%2F60=2%2F15\" hour
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\n" ); document.write( "Let t = time for John to finish the race\r
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\n" ); document.write( "\n" ); document.write( "______________speed_____________time_______________distance(km)
\n" ); document.write( "Danny_________(___)_____________t-8/60_____________20
\n" ); document.write( "John_________(____)______________t_________________20\r
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\n" ); document.write( "\n" ); document.write( "Danny is at a rate r+5, if John went at a rate of r. The rates are unknown.
\n" ); document.write( "This and also reducing the time expression for Danny,...\r
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\n" ); document.write( "\n" ); document.write( "______________speed_____________time_______________distance(km)
\n" ); document.write( "Danny_________(r+5)_____________t-2/15_____________20
\n" ); document.write( "John_________(r)_________________t_________________20\r
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\n" ); document.write( "\n" ); document.write( "A rate*time=distance equation can be made for each of Danny and John.\r
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\n" ); document.write( "\n" ); document.write( "John: \"highlight_green%28rt=20%29\", which can also be used as \"highlight_green%28t=20%2Fr%29\"\r
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\n" ); document.write( "\n" ); document.write( "Danny: \"%28r%2B5%29%28t-2%2F15%29=20\"
\n" ); document.write( "\"rt%2B5t-2r%2F15-2%2F3=20\"
\n" ); document.write( "Substituting with John's equation,
\n" ); document.write( "\"20%2B5t-2r%2F15-2%2F3=20\"
\n" ); document.write( "\"5t-2r%2F15-2%2F3=0\"
\n" ); document.write( "Multiply members by 15 to clear the denominators
\n" ); document.write( "\"75t-2r-10=0\"
\n" ); document.write( "Make use of John's equation:
\n" ); document.write( "\"75%2820%2Fr%29-2r-10=0\"
\n" ); document.write( "\"1500%2Fr-2r-10=0\"
\n" ); document.write( "\"1500-2r%5E2-10r=0\"
\n" ); document.write( "\"-2r%5E2-10r%2B1500=0\"
\n" ); document.write( "\"highlight_green%28r%5E2%2B5r-750=0%29\"----Quadratic equation in r, the rate for John.
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\n" ); document.write( "Use the * general solution to a quadratic equation to solve for r, even through the question really just asks for Danny's rate; both rates are given a relationship in the description.
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\n" ); document.write( "* The quadratic expression on the left hand side is factorable, so you might be able to explore the factorizations of 750, but you will find that the equation is \"highlight%28%28r-30%29%28r%2B25%29=0%29\".
\n" ); document.write( "The meaningful answer is, \"highlight%28highlight%28r=30%29%29\". This means, Danny's rate was 35 kilometers per hour.
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