document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=833262>Question 833262</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could anyone help me with this problem?\r<BR>\n" );
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document.write( "Suppose that women's heights are normally distributed w/ mean=63.6 inches & standard deviation=2.5 inches. Find the probability that<BR>\n" );
document.write( "(a) if 1 woman is randomly selected that her height is less than 60 inches.<BR>\n" );
document.write( "(b) if 36 are randomly selected, that they have a mean height less than 60 inches </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502508 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502508\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose that women's heights are normally distributed w/ mean=63.6 inches & standard deviation=2.5 inches. Find the probability that<BR>\n" );
document.write( "(a) if 1 woman is randomly selected that her height is less than 60 inches.<BR>\n" );
document.write( "z(60) = (60-63.6)/2.5 = -3.6/2.5 = -1.44<BR>\n" );
document.write( "P(x < 60) = P(z < -1.44) = normalcdf(-100,-1.44) = 0.0749<BR>\n" );
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document.write( "(b) if 36 are randomly selected, that they have a mean height less than 60 inches<BR>\n" );
document.write( "z(60) = (60-63.6)/[2.5/sqrt(36) = 6*-1.44 = -8.64<BR>\n" );
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document.write( "P(x-bar < 60) = P(z < -8.64) = normalcdf(-100,-8.64) = 0 to 4 decimals.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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