document.write( "Question 833374: The length of a rectangular garden is 3 meters more than its width. If the perimeter of the garden is 50 meters, what is the area of the rectangle? Thankyou. :) \n" ); document.write( "
Algebra.Com's Answer #502505 by Leaf W.(135)\"\" \"About 
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\n" ); document.write( "Let us call the width of the garden (in meters) \"x.\"
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\n" ); document.write( "Since the length is 3 meters greater than the width, the length = x + 3.
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\n" ); document.write( "Now form an equation using these expressions to show the perimeter of the garden:
\n" ); document.write( "Perimeter = 2*width + 2*length
\n" ); document.write( "Perimeter = 2x + 2(x + 3)
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\n" ); document.write( "As we know that the perimeter is 50 meters, we can plug this in and solve for x:
\n" ); document.write( "50 = 2x + 2(x + 3)
\n" ); document.write( "50 = 2x + 2x + 6
\n" ); document.write( "44 = 4x
\n" ); document.write( "4x = 44
\n" ); document.write( "x = 11
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\n" ); document.write( "Therefore, the width = 11 meters. To solve for the length, just plug x = 11 into the expression for length: length = x + 3 = 11 + 3 = 14.
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\n" ); document.write( "Now we know that the width = 11 meters and the length = 14 meters.
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\n" ); document.write( "To find the area, just plug these values into the area formula for a rectangle:
\n" ); document.write( "Area = length*width
\n" ); document.write( "Area = 14*11
\n" ); document.write( "Area = 154
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\n" ); document.write( "Therefore, the area of the rectangular garden is 154 square meters. =) \n" ); document.write( "
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