document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89>Question 89</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We have a rectangle where 2x+2y=45, and x=2/3y, solve for x (or Y).\r<BR>\n" );
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document.write( "How do you solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502497 by </B><A HREF=/tutors/aboutme.mpl?userid=dreamgirl9999><B>dreamgirl9999(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dreamgirl9999><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First you replace the x in 2x+2y=45 with 2/3y since x=2/3y.<BR>\n" );
document.write( "After doing this you should get 2(2/3y)+2y=45.<BR>\n" );
document.write( "Now distribute and you should get 1_1/3y (or 4/3) +2y=45.<BR>\n" );
document.write( "After combining the like terms: 3_1/3y=45<BR>\n" );
document.write( "Now do the inverse operations by dividing by 3_1/3 on both sides to get y by itself:: y=13_1/2<BR>\n" );
document.write( "Answers are y=13_1/2 (or 13.5) and x=9 (you get 9 by multiplying 2/3 by 13.5). </SPAN>\n" );
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