document.write( "Question 833333: Jane bought a certain number of oranges at 45^c each, and the same number of oranges of oranges at 35^c each. She paid $44.00 for the oranges.
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Algebra.Com's Answer #502492 by KMST(5328)\"\" \"About 
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HOW TO THINK THROUGH THE PROBLEM FOR MULTIPLE CHOICE:
\n" ); document.write( "If she bought the same number of oranges at each price, then the average price she paid was
\n" ); document.write( "\"%2845%5Ec%2B35%5Ec%29%2F2=40%5Ec\" per orange, so she must have bought
\n" ); document.write( "\"%22%24+44.00%22%2F%22%24+0.40+%2F+orange%22=110\"\"oranges\" .
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\n" ); document.write( "TO EXPLAIN WITH \"show your work\":
\n" ); document.write( "\"x\"= number of oranges bought at each price.
\n" ); document.write( "($0.45)x + ($0.35)x = $44.00
\n" ); document.write( "\"0.44x%2B0.35x+=+44\"
\n" ); document.write( "\"%280.44%2B0.35%29x+=+44\"
\n" ); document.write( "\"%280.80%29x+=+44\"
\n" ); document.write( "\"x=44%2F0.80\"
\n" ); document.write( "\"x=55\"
\n" ); document.write( "So Jane bought a total =\"2x=2%2A55=highlight%28110%29\" oranges.
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