document.write( "Question 833222: if the width of a rectangle is four feet less than the length and the perimeter is 68 feet, what are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #502469 by JulietG(1812)\"\" \"About 
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P = 2L + 2W
\n" ); document.write( "P = 68
\n" ); document.write( "W = L-4
\n" ); document.write( "Let's plug in the values
\n" ); document.write( "68 = 2L + 2(L-4) [substituting the width value]
\n" ); document.write( "68 = 2L + 2L - 8
\n" ); document.write( "Add 8 to each side, and add the Ls
\n" ); document.write( "76 = 4L
\n" ); document.write( "Divide each side by 4
\n" ); document.write( "L = 19
\n" ); document.write( ".
\n" ); document.write( "If L = 19, then W = L-4, or 15
\n" ); document.write( ".
\n" ); document.write( "Check by putting in the numbers
\n" ); document.write( "68 = (2*19) + (2*15)
\n" ); document.write( "68 = 38 + 38
\n" ); document.write( "Success!
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