document.write( "Question 833222: if the width of a rectangle is four feet less than the length and the perimeter is 68 feet, what are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #502469 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! P = 2L + 2W \n" ); document.write( "P = 68 \n" ); document.write( "W = L-4 \n" ); document.write( "Let's plug in the values \n" ); document.write( "68 = 2L + 2(L-4) [substituting the width value] \n" ); document.write( "68 = 2L + 2L - 8 \n" ); document.write( "Add 8 to each side, and add the Ls \n" ); document.write( "76 = 4L \n" ); document.write( "Divide each side by 4 \n" ); document.write( "L = 19 \n" ); document.write( ". \n" ); document.write( "If L = 19, then W = L-4, or 15 \n" ); document.write( ". \n" ); document.write( "Check by putting in the numbers \n" ); document.write( "68 = (2*19) + (2*15) \n" ); document.write( "68 = 38 + 38 \n" ); document.write( "Success! \n" ); document.write( " |