document.write( "Question 833303: the perimeter of a rectangle is 32cm. the difference between the length and the width is 4 cm. find the width \n" ); document.write( "
Algebra.Com's Answer #502450 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! Perimeter = 2 length + 2 width \n" ); document.write( "P = 32 \n" ); document.write( "L = W+4 \n" ); document.write( "Now plug in the numbers: \n" ); document.write( "32 = 2L + 2W \n" ); document.write( "Substitute the value of L \n" ); document.write( "32 = 2(W+4) + 2W \n" ); document.write( "32 = 2W + 8 + 2W \n" ); document.write( "Subtract 8 from each side \n" ); document.write( "24 = 4W \n" ); document.write( "Divide each side by 4 \n" ); document.write( "6 = W \n" ); document.write( "If the width is 6, the length is W+4, or 10 \n" ); document.write( " |