document.write( "Question 70490:  please help me solve this\r
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document.write( "z+7/9+1 = 2z+1/6 \n" );
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| Algebra.Com's Answer #50245 by checkley75(3666)      You can put this solution on YOUR website! Z+7/9+1=2Z+1/6 \n" ); document.write( "Z-2Z=1/6-7/8-1 \n" ); document.write( "-3Z=(4-3*7-24)/24 \n" ); document.write( "-3Z=(4-21-24)/24 \n" ); document.write( "-3Z=-41/24 \n" ); document.write( "Z=-41/24*-1/3 \n" ); document.write( "Z=41/72 \n" ); document.write( "---------------------------------- \n" ); document.write( "(Z+7)/9+1=(2Z+1)/6 YOU NEED TO USE ( ) AROUND THE COMPLEX NUMERATORS. \n" ); document.write( "(Z+7+9)/9=(2Z+1)/6 \n" ); document.write( "(Z+16)/9=(2Z+1)/6 NOW CROSS MULTIPLY \n" ); document.write( "9(2Z+1)=6(Z+16) \n" ); document.write( "18Z+9=6Z+96 \n" ); document.write( "18Z-6Z=96-9 \n" ); document.write( "12Z=87 \n" ); document.write( "Z=87/12 \n" ); document.write( "Z=7.25 ANSWER \n" ); document.write( "HOPE THIS IS THE RIGHT ANSWER!!!!!!!\r \n" ); document.write( "\n" ); document.write( "USE ( ) WHEN IN DOUBT. \n" ); document.write( " |