document.write( "Question 70490: please help me solve this\r
\n" ); document.write( "\n" ); document.write( "z+7/9+1 = 2z+1/6
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Algebra.Com's Answer #50245 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
Z+7/9+1=2Z+1/6
\n" ); document.write( "Z-2Z=1/6-7/8-1
\n" ); document.write( "-3Z=(4-3*7-24)/24
\n" ); document.write( "-3Z=(4-21-24)/24
\n" ); document.write( "-3Z=-41/24
\n" ); document.write( "Z=-41/24*-1/3
\n" ); document.write( "Z=41/72
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\n" ); document.write( "(Z+7)/9+1=(2Z+1)/6 YOU NEED TO USE ( ) AROUND THE COMPLEX NUMERATORS.
\n" ); document.write( "(Z+7+9)/9=(2Z+1)/6
\n" ); document.write( "(Z+16)/9=(2Z+1)/6 NOW CROSS MULTIPLY
\n" ); document.write( "9(2Z+1)=6(Z+16)
\n" ); document.write( "18Z+9=6Z+96
\n" ); document.write( "18Z-6Z=96-9
\n" ); document.write( "12Z=87
\n" ); document.write( "Z=87/12
\n" ); document.write( "Z=7.25 ANSWER
\n" ); document.write( "HOPE THIS IS THE RIGHT ANSWER!!!!!!!\r
\n" ); document.write( "\n" ); document.write( "USE ( ) WHEN IN DOUBT.
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