document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=833308>Question 833308</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x-3y=-1<BR>\n" );
document.write( "2x-7y=-1 <BR>\n" );
document.write( " substitution method  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502447 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-3y=-1<BR>\n" );
document.write( "2x-7y=-1 <BR>\n" );
document.write( ".<BR>\n" );
document.write( "Add 3y to each side of the first equation<BR>\n" );
document.write( "x = 3y-1<BR>\n" );
document.write( "Now take that value and substitute it for the x value in the second equation<BR>\n" );
document.write( "2(3y-1) - 7y =-1<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "6y-2-7y = -1<BR>\n" );
document.write( "Add 2 to each side<BR>\n" );
document.write( "6y-7y = 1<BR>\n" );
document.write( "Subtract<BR>\n" );
document.write( "-y = 1<BR>\n" );
document.write( "Multiply by -1 on each side<BR>\n" );
document.write( "y = -1<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If y is -1, then x is (3*-1)-1, -3-4 = -4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );