document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=833169>Question 833169</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a swimming pool is 30 m long and 10 m wide. the depth of water increases uniformly from 1m to 3m. find the volume of the water in the pool. (hint:think of the cross section of the pool) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502397 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One can think of the cross section of the pool as <BR>\n" );
document.write( "a rectangle 1m by 30m over a triangle that is<BR>\n" );
document.write( "30m across the top with a depth at one end of 2m.<BR>\n" );
document.write( "So the cross sectional area is<BR>\n" );
document.write( "(1 * 30) + 1/2(2 * 30) = 2 * 30 = 60<BR>\n" );
document.write( "Now if we multiply 60 x 10 we will find we have <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=600+m%5E3 ALIGN=MIDDLE  ALT=\"600+m%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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