document.write( "Question 833193: Given y=-2/3x+1, write the equation of the line that is perpendicular and passes through the point (6,2) in slope intercept form. \n" ); document.write( "
Algebra.Com's Answer #502377 by LinnW(1048)\"\" \"About 
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y=-2/3x+1
\n" ); document.write( "let m = slope
\n" ); document.write( "To be perpendicular we need slope to be negative inverse
\n" ); document.write( "so (-2/3)*m = -1
\n" ); document.write( "To solve for m, multiply each side by -3/2
\n" ); document.write( "(-3/2)(-2/3)*m=(-3/2)(-1)
\n" ); document.write( "m = 3/2
\n" ); document.write( "Another way to think about this is to invert and change the sign.
\n" ); document.write( "Using y = mx + b as a template, we want to solve for b.
\n" ); document.write( "Since we want to go through (6,2), x=6 and y=2.
\n" ); document.write( "y = mx + b becomes
\n" ); document.write( "2 = (3/2)(6) + b
\n" ); document.write( "2 = 9 + b
\n" ); document.write( "subtract 9 from each side
\n" ); document.write( "-7 = b
\n" ); document.write( "Our equation is y = (3/2)x - 7
\n" ); document.write( "To verify, substitute 6 for x
\n" ); document.write( "y = (3/2)(6) - 7
\n" ); document.write( "y = 9 - 7
\n" ); document.write( "y = 2
\n" ); document.write( "So for the point y = (3/2)x -7 passes through (6,2) \n" ); document.write( "
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