document.write( "Question 833147: 600 invested for 3 years at 25%\r
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document.write( "What is the interest per year \n" );
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Algebra.Com's Answer #502310 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! I'd love to see the prospectus for an investment that pays 25%! \n" ); document.write( "This assumes that it is simple interest, paid yearly. \n" ); document.write( "First year, 600 * 0.25 = 150 interest \n" ); document.write( "Second year (600+150) * 0.25 = 187.50 interest \n" ); document.write( "Third year (600+150+187.50) * 0.25 = 234.38 interest \n" ); document.write( ". \n" ); document.write( "At the end of the third year, you'll have \n" ); document.write( "600 (initial) + 150 (yr 1 interest) + 287.50 (yr 2 interest) + 187.50 (yr 3 interest) \n" ); document.write( " \n" ); document.write( " |