document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=833117>Question 833117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation Two consecutive numbersare such that the greater added thrice the smaller makes a total of 53 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502300 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> B = A + 1 (consecutive)<BR>\n" );
document.write( "B + 3A = 53<BR>\n" );
document.write( "Substitute the value that we know for B<BR>\n" );
document.write( "B + 3A = 53<BR>\n" );
document.write( "(A+1) + 3A = 53<BR>\n" );
document.write( "4A + 1 = 53<BR>\n" );
document.write( "subtract 1 from each side<BR>\n" );
document.write( "4A = 52<BR>\n" );
document.write( "divide by 4<BR>\n" );
document.write( "A = 13<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If A is 13, then B is 14.<BR>\n" );
document.write( "Let's make sure it works.<BR>\n" );
document.write( "14 + (3*13) = 53<BR>\n" );
document.write( "14 + 39 does indeed equal 53<BR>\n" );
document.write( "success!  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );