document.write( "Question 70445: A blue spruce grows an average of 6 in per year. A hemlock grows an average of 4 in per year. If a blue spurce is 4 feet tall and a hemlock is 6 feet tall, when would you expect the trees to be the same height?\r
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Algebra.Com's Answer #50230 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
(48+6X)=(72+4X)
\n" ); document.write( "48+6X=72+4X
\n" ); document.write( "6X-4X=72-48
\n" ); document.write( "2X=24
\n" ); document.write( "X=24/2
\n" ); document.write( "X=12 YEARS THE TWO TREES WILL BE @ THE SAME HEIGHT.
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