document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70430>Question 70430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> word problem.\r<BR>\n" );
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document.write( "The sum of twice one number and three times another is 41. If the second is subtracted from the first, the diference is 8. what are the numbers ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50228 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2X+3Y=41<BR>\n" );
document.write( "X-Y=8 X=Y+8 NOW SUBSTITUTE (Y+8) FOR X & SOLVE FOR Y<BR>\n" );
document.write( "2(Y+8)+3Y=41<BR>\n" );
document.write( "2Y+16+3Y=41<BR>\n" );
document.write( "5Y=41-16<BR>\n" );
document.write( "5Y=25<BR>\n" );
document.write( "Y=25/5<BR>\n" );
document.write( "Y=5 ANSWER NOW SUBSTITUTE 5 FOR Y & SOLVE FOR X<BR>\n" );
document.write( "X-5=8<BR>\n" );
document.write( "X=8+5<BR>\n" );
document.write( "X=13 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2*13+3*5=41<BR>\n" );
document.write( "26+15=41<BR>\n" );
document.write( "41=41<BR>\n" );
document.write( "  </SPAN>\n" );
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