document.write( "Question 70425: Carla invested $28,000, part at 14% and part at 9%. If the total interest at the end of the year is $3,370, how muc did she invest at 14%\r
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Algebra.Com's Answer #50226 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
.14x+.09(28000-x)=3370
\n" ); document.write( ".14x+2520-.09x=3370
\n" ); document.write( ".14x-.09x=3370-2520
\n" ); document.write( ".05x=850
\n" ); document.write( "x=850/.05
\n" ); document.write( "x=17000 amount invested @ 14%
\n" ); document.write( "28000-17000=11000 invested @ 9%
\n" ); document.write( "proof
\n" ); document.write( "17000*.14+11000*.09=3370
\n" ); document.write( "2380+990=3370
\n" ); document.write( "3370=3370
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