document.write( "Question 832694: cos3 + jsin3 / cos2 +jsin \n" ); document.write( "
Algebra.Com's Answer #502249 by stanbon(75887)\"\" \"About 
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(cos3 + jsin3) / (cos2 +jsin)
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\n" ); document.write( "Multiply numerator and denominator by cos(2)-jsin(2) to get:
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\n" ); document.write( "= [(cos(3)+jsin(3))(cos(2)-jsin(2)]/[cos^2(2)+sin^2(2)]
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\n" ); document.write( "= [cos(3)cos(2) + sin(3)sin(2)]/1
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\n" ); document.write( "= cos(3-2)
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\n" ); document.write( "= cos(1)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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