document.write( "Question 70389This question is from textbook College Algebra
\n" ); document.write( ": Maria can sew a dress in 10 hours less time than Stephanie. Together both women can sew a dress in 17 hours. How long would it take if Stephanie works alone? \n" ); document.write( "
Algebra.Com's Answer #50224 by checkley75(3666)\"\" \"About 
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s*m/(s+m)=17 s=x & m=(x-10
\n" ); document.write( "x(x-10)/(x+x-10)=17
\n" ); document.write( "(x^2-10x)/(2x-10)=17 now cross multiply
\n" ); document.write( "17(2x-10)=x^2-10x
\n" ); document.write( "34x-170=x^2-10x
\n" ); document.write( "x^2-10x-34x+170=0
\n" ); document.write( "x^2-44x+170=0
\n" ); document.write( "using the quadratic equation to solve this problem we have
\n" ); document.write( "x=(-b+-sqrt[b^2-4ac])/2a
\n" ); document.write( "x=(44+-sqrt(-44^2)-4*1*170])/2
\n" ); document.write( "x=(44+-sqrt1936-680])/2
\n" ); document.write( "x=(44+-sqrt1256)/2
\n" ); document.write( "x=44+-35.44)/2
\n" ); document.write( "x=79.44/2
\n" ); document.write( "x=39.72 hours for Stephanie to sew a dress alone.
\n" ); document.write( "39.72-10=29.72 hours for Marie to sew a dress alone.
\n" ); document.write( "proof
\n" ); document.write( "(39.72*29.72)/(39.72+29.72)=17
\n" ); document.write( "1180.5/69.44=17
\n" ); document.write( "17=17 \n" ); document.write( "
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