document.write( "Question 832791: 5x + 3 > 4x + 7. \r
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Algebra.Com's Answer #502192 by beamqueen28(1)![]() ![]() ![]() You can put this solution on YOUR website! 5x+3>4x+7 \n" ); document.write( " \n" ); document.write( "SUBTRACT 4X ON BOTH SIDES TO GET THE VARIABLE ON ONE SIDE\r \n" ); document.write( "\n" ); document.write( " 5x+3>4x+7 \n" ); document.write( " -4x -4x \n" ); document.write( "_________________ \n" ); document.write( "x+3>7\r \n" ); document.write( "\n" ); document.write( "SUBTRACT 3 ON BOTH SIDES TO HAVE THE NUMBERS ON ONE SIDE\r \n" ); document.write( "\n" ); document.write( "x+3>7 \n" ); document.write( " -3 -3 \n" ); document.write( "__________ \n" ); document.write( "x>4 \r \n" ); document.write( "\n" ); document.write( "If you plug in 4 for x you get both sides equaling 23. This proves that x must be greater than 4. (You can treat the inequality sign like an equal sign.)\r \n" ); document.write( "\n" ); document.write( "I hope this helped you. \n" ); document.write( " \n" ); document.write( " |