document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70401>Question 70401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times one number added to another number is 18. Twice the first number number minus the other number is 12. Find the numbers. \r<BR>\n" );
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document.write( "I ahve 5 and 9. Is this correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50216 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50216\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+y=18 y=18-3x<BR>\n" );
document.write( "2x-y=12 now substitute (18-3x) for y in this equation 7 solve for x<BR>\n" );
document.write( "2x-(18-3x)=12<BR>\n" );
document.write( "2x-18+3x=12<BR>\n" );
document.write( "5x=30<BR>\n" );
document.write( "x=30/5<BR>\n" );
document.write( "x=6 answer now substitute 6 for x & solve for y<BR>\n" );
document.write( "3*6+y=18<BR>\n" );
document.write( "18+y=18<BR>\n" );
document.write( "y=18-18<BR>\n" );
document.write( "y=0 answer<BR>\n" );
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