document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=832591>Question 832591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is 3 years less than 5 times his sons age. The sum of their ages 37. Determine the fathers age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502157 by </B><A HREF=/tutors/aboutme.mpl?userid=thejackal><B>thejackal(72)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thejackal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=thejackal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the son's age be s, therefore the<BR>\n" );
document.write( "Function of the Man's age = 5s - 3<BR>\n" );
document.write( "thus (5s-3)+s = 37\r<BR>\n" );
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document.write( "simplifies to 6s - 3 = 37, 6s = 40; thus the sons age s = (40/6)\r<BR>\n" );
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document.write( "therefore the fathers age is 5(40/6) - 3 = (91/3) years\r<BR>\n" );
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document.write( "remember to leave your answer in fractions to maintain precision otherwise, if if you round off you will get rounding errors that lead to the wrong answer.\r<BR>\n" );
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document.write( "to confirm,\r<BR>\n" );
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document.write( "(91/3)+(40/6) = (222/6) exactly = 37 years </SPAN>\n" );
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