document.write( "Question 832240: How do you find the P and the directrix of the equation of a parabola with its focus on (4,-2) and a vertex of (4,-4)? \r
\n" ); document.write( "\n" ); document.write( "I tried solving for P but I don't know if it's correct. Here's my solution for P:\r
\n" ); document.write( "\n" ); document.write( "Since focus is (h + P, k) in terms of y or (h, P + k)in terms of x, I don't know if the equation is in terms of y or x, so I just made a guess, so: (4 + P, -4); P=-4 or (4, P - 4); P=4? \r
\n" ); document.write( "\n" ); document.write( "And also, how do you find P if vertex is at (2,1) and the directrix is at x = -2?\r
\n" ); document.write( "\n" ); document.write( "I'm really confused in finding for P but I understand how the basics work in conic sections. Your help will be really appreciated.\r
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Algebra.Com's Answer #502153 by lwsshak3(11628)\"\" \"About 
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How do you find the P and the directrix of the equation of a parabola with its focus on (4,-2) and a vertex of (4,-4)?
\n" ); document.write( "how do you find P if vertex is at (2,1) and the directrix is at x = -2?
\n" ); document.write( "***
\n" ); document.write( "In the first case, parabola opens upward.
\n" ); document.write( "Its basic equation: (x+h)^2=4p(y-k)
\n" ); document.write( "(x-4)^2=4p(y+4)
\n" ); document.write( "axis of symmetry: x=4
\n" ); document.write( "focus: (4,-2)
\n" ); document.write( "p=2 (distance(-2 to -4) from focus to vertex on the axis of symmetry)
\n" ); document.write( "directrix: y=-6
\n" ); document.write( "..
\n" ); document.write( "In the 2nd case, parabola opens rightward.
\n" ); document.write( "axis of symmetry: y=1
\n" ); document.write( "p=4 (distance(-2 to 2) from directrix to vertex on the axis of symmetry)
\n" ); document.write( "focus: (6,1)
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