document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=832659>Question 832659</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The *width* of a rectangular garden is one-third its length, and its perimeter is 32 m. Find the dimensions of this garden. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502134 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2 length + 2 width<BR>\n" );
document.write( "P = 32<BR>\n" );
document.write( "W = 1/3L<BR>\n" );
document.write( "Substitute the value of W into the original equation:<BR>\n" );
document.write( "32 = 2L + 2(1/3L)<BR>\n" );
document.write( "32 = 2L + 2/3L<BR>\n" );
document.write( "32 = 2 2/3 L or 8/3 L<BR>\n" );
document.write( "Multiply each side by 3 to get rid of the fraction<BR>\n" );
document.write( "32*3 = 8L<BR>\n" );
document.write( "96 = 8L<BR>\n" );
document.write( "Divide each side by 8<BR>\n" );
document.write( "12 = L<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Now that you have the length, you can tell the width -- 1/3 of the length, or 4. </SPAN>\n" );
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