document.write( "Question 832615: 2/3a-5=1/3a+5\r
\n" ); document.write( "\n" ); document.write( "Please help me by showing the work to get a solution,
\n" ); document.write( "I don't want the answer given to me, just need help on how to get there
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Algebra.Com's Answer #502104 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
The way my brain works, I can't stand those pesky fractions. There are probably a dozen ways to solve this, but getting rid of the fraction is simplest for me. Whatever works!
\n" ); document.write( "2/3a-5=1/3a+5
\n" ); document.write( "If we multiply each side by 3, we can get rid of the fractions
\n" ); document.write( "2/3 * 3 = 2 and 1/3 * 3 = 1
\n" ); document.write( "3(2/3-5) = 3(1/3+5)
\n" ); document.write( "Distribute
\n" ); document.write( "2a-15 = 1a + 15
\n" ); document.write( "Subtract 1a from each side
\n" ); document.write( "1a - 15 = 15
\n" ); document.write( "Add 15 to each side
\n" ); document.write( "a = 30
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\n" ); document.write( "The key is to isolate the variable. Remember that whatever you do to one side, do the same to the other.
\n" ); document.write( "Let's plug this in to see if it's correct.
\n" ); document.write( "2/3a-5=1/3a+5
\n" ); document.write( "2/3*30 - 5 = 1/3*30 + 5
\n" ); document.write( "20 - 5 = 10 + 5
\n" ); document.write( "Success!
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