document.write( "Question 9317: A freight train left Beeville at 5am traveling 30mph. At 7am an express train traveling 50 mph left the same station. When did the express overtake the freight? (I believe I know the answer, I just don't know how to set it up into a table. I believe both trains meet at 10 A.M.) \n" ); document.write( "

Algebra.Com's Answer #5021 by rapaljer(4671) $\"\"$ $\"About$

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The express overtakes the freight train when distance = distance, or in other words when $\"r%2At+=+r%2At\"$ . Let x = time of the express to overtake the freight train. Then x+2 = time of the freight train (since it is slower, the time is greater than the express),\r
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\n" ); document.write( "\n" ); document.write( "30(x+2) = 50(x)
\n" ); document.write( "30x + 60 = 50x\r
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\n" ); document.write( "\n" ); document.write( "Subtract 30x from each side:
\n" ); document.write( "30x - 30x + 60 = 50x - 30x
\n" ); document.write( "60 = 20x
\n" ); document.write( "3 = x \r
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\n" ); document.write( "\n" ); document.write( "The express overtakes the freight train 3 hours after it left at 7 a.m., which you correctly said is at 10 am.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( "

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