document.write( "Question 831986: Albert rolls a number cube and records the results in the table. Find the experimental probabilities.\r
\n" ); document.write( "\n" ); document.write( "Number 1 2 3 4 5 6
\n" ); document.write( "# of rolls 11 15 8 15 11 6\r
\n" ); document.write( "\n" ); document.write( "a) P(2)= 15?\r
\n" ); document.write( "\n" ); document.write( "b) P(1or5)= ???\r
\n" ); document.write( "\n" ); document.write( "C) P(not a 5)=???\r
\n" ); document.write( "\n" ); document.write( "d) P(6)=6?\r
\n" ); document.write( "\n" ); document.write( "I tried a)and d) I am not sure if they are right and I think b) might be 11 but I am really not sure and need help to solve c)
\n" ); document.write( "Please help. My parents are not able to help with this.
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Algebra.Com's Answer #502007 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Probabilities are outcomes that you're interested in divided by total outcomes.
\n" ); document.write( "Probabilities are always at least zero and at most 1.
\n" ); document.write( "Albert rolled the cube \"11%2B15%2B8%2B15%2B11%2B6\" times or \"66\" times.
\n" ); document.write( "a) P(2)=\"15%2F66=5%2F22\"
\n" ); document.write( "b) P(1 or 5)=P(1)+P(5)=\"11%2F66%2B11%2F66=1%2F6%2B1%2F6=2%2F3\"
\n" ); document.write( "c) P(not a 5) means P(everything but a 5)=\"1-P%285%29=1-11%2F66=1-1%2F6=5%2F6\"
\n" ); document.write( "You could also get it by summing all the probabilities of the other numbers,
\n" ); document.write( "P(not a 5)=P(1)+P(2)+P(3)+P(4)+P(6)=\"11%2F66%2B15%2F66%2B8%2F66%2B15%2F66%2B6%2F66=55%2F66=5%2F6\"
\n" ); document.write( "d) P(6)=6/66=\"1%2F11\"
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