document.write( "Question 832357: THREE YEARS AGO NAVIN AND PAMMI HAD AN AVERAGE AGE OF 18YEARS.WITH SUBHA JOINING THEM NOW THEIR AVERAGE BECAME 22YEARS.WHAT IS SUBHA'S AGE NOW?
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Algebra.Com's Answer #501997 by hovuquocan1997(83)\"\" \"About 
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Let the age of Navin be x, the age of Pammi be y, and the age of Subha be z
\n" ); document.write( "Now you have, three years ago, means you will have x-3, and y-3
\n" ); document.write( "The average is 18, so your equation will be
\n" ); document.write( "\"%28%28x-3%29+%2B+%28y-3%29%29%2F2+=+18\"
\n" ); document.write( "\"%28x%2By-6%29%2F2+=+18\"
\n" ); document.write( "\"x%2By+-+6+=+36\"
\n" ); document.write( "\"x%2By+=+42\"
\n" ); document.write( "Now you have x+y = 42
\n" ); document.write( "Now you have the average of x, y, and z are 22, so you have the equation:
\n" ); document.write( "\"%28x%2By%2Bz%29%2F3+=+22\"
\n" ); document.write( "\"x%2By%2Bz+=+66\"
\n" ); document.write( "But you have x+y = 42, so let's plug it in
\n" ); document.write( "\"x%2By%2Bz+=+66\"
\n" ); document.write( "\"42+%2B+z+=+66\"
\n" ); document.write( "\"z+=+24\"
\n" ); document.write( "TA-DAH
\n" ); document.write( ":D
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