document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=832358>Question 832358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the price of kerosene is increased by #6(#-NAIRA) per litre, find the new price per litre if two thirds of the new price is equal to five sevenths of the old price. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501994 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501994\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the price of kerosene is increased by #6(#-NAIRA) per litre, find the new price per litre if two thirds of the new price is equal to five sevenths of the old price.<BR>\n" );
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document.write( "Let original price be \"x\".<BR>\n" );
document.write( "New price is \"x+6\"<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "(2/3)(x+6) = (5/7)x<BR>\n" );
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document.write( "Multiply both sides by 21 to get:<BR>\n" );
document.write( "14(x+6) = 15x<BR>\n" );
document.write( "x = 14*6<BR>\n" );
document.write( "x = #84<BR>\n" );
document.write( "x+6 = #90<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================== </SPAN>\n" );
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