document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=832338>Question 832338</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 1 is a root of the equation 5x^2 +kx-3=0,find the other root. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501990 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501990\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 1 is a root of the equation 5x^2 +kx-3=0,find the other root.<BR>\n" );
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document.write( "Using synthetic division::<BR>\n" );
document.write( "1)....5....k....-3<BR>\n" );
document.write( "......5....k+5..|..K+2\r<BR>\n" );
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document.write( "Solve:: k+2 = 0<BR>\n" );
document.write( "k = -2<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "y = 5x^2 -2x -3<BR>\n" );
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document.write( "Factor: y = (x-1)(5x+3)<BR>\n" );
document.write( "Other root:: x = -3/5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=============== </SPAN>\n" );
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