document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=832311>Question 832311</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (1/2) Find the length and width of a rectangle the perimeter is 80m. The length is 4 times the width. Okay so what would the eqution be </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501986 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2W + 2L = P where W is width, L is length and P is perimeter<BR>\n" );
document.write( "L = 4W  Substitute 4W for L and 80 for P<BR>\n" );
document.write( "2W + 2(4W) = 80<BR>\n" );
document.write( "2W + 8W = 80<BR>\n" );
document.write( "10W = 80<BR>\n" );
document.write( "W = 8<BR>\n" );
document.write( "L = 4W = 4(8) = 32\r<BR>\n" );
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