document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70366>Question 70366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the axis of symmetry:<BR>\n" );
document.write( "y = x^2 - x + 10\r<BR>\n" );
document.write( "\n" );
document.write( "I can not seem to understand this method, I did look back at some other ones, but felt it confused me even more, help please, thank you!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50197 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50197\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the axis of symmetry:<BR>\n" );
document.write( "y = x^2 - x + 10 <BR>\n" );
document.write( "Rewrite as follows:<BR>\n" );
document.write( "x^2-x+10 = y<BR>\n" );
document.write( "Set it up for completing the square:<BR>\n" );
document.write( "x^2-x+? = y-10+?<BR>\n" );
document.write( "Complete the square and keep the equation balanced.<BR>\n" );
document.write( "x^2-x+(1/2)^2 = y-10+(1/2)^2<BR>\n" );
document.write( "Factor the left side and simplify the right to get:<BR>\n" );
document.write( "(x-(1/2))^2 = y-(39/4)<BR>\n" );
document.write( "The vertex is at (1/2,(39/4))<BR>\n" );
document.write( "So the axis of symmetry is x=(1/2)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );