document.write( "Question 832333: log2(x^2-x)=1 \n" ); document.write( "

Algebra.Com's Answer #501968 by nerdybill(7384) $\"\"$ $\"About$

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log2(x^2-x)=1
\n" ); document.write( "x^2-x= 2^1
\n" ); document.write( "x^2-x= 2
\n" ); document.write( "x^2-x-2 = 0
\n" ); document.write( "(x+1)(x-2) = 0
\n" ); document.write( "x = {-1,2}
\n" ); document.write( " \n" ); document.write( "

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