document.write( "Question 832320: J.D. Power and Associates says that 60 percent of car buyers now use the Internet for research and price comparisons.
\n" ); document.write( "1.Find the probability that in a sample of 5 car buyers, all 5 will use the Internet. Answer is .0778\r
\n" ); document.write( "\n" ); document.write( "2.Find the probability that in a sample of 5 car buyers, at least 2 will use the Internet. \r
\n" ); document.write( "\n" ); document.write( "3.Find the probability that in a sample of 5 car buyers, more than 1 will use the Internet\r
\n" ); document.write( "\n" ); document.write( "4.Find the mean and standard deviation of the probability distribution
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Algebra.Com's Answer #501965 by stanbon(75887)\"\" \"About 
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J.D. Power and Associates says that 60 percent of car buyers now use the Internet for research and price comparisons.
\n" ); document.write( "1.Find the probability that in a sample of 5 car buyers, all 5 will use the Internet. Answer is .0778
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\n" ); document.write( "2.Find the probability that in a sample of 5 car buyers, at least 2 will use the Internet.
\n" ); document.write( "P(2<= x <=5) = 1 - P(0<= x <=1) = 1-binomcdf(5,0.6,1) = 0.9130
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\n" ); document.write( "3.Find the probability that in a sample of 5 car buyers, more than 1 will use the Internet
\n" ); document.write( "Ans: Same as answer to #2.
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\n" ); document.write( "4.Find the mean and standard deviation of the probability distribution
\n" ); document.write( "mean = np = 5*0.6 = 0.3
\n" ); document.write( "std = sqrt(npq) = sqrt(0.3*0.4) = 0.3464
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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