document.write( "Question 832281: I can walk to work at 4mph or cycle at 12mph and I save ten minutes if I ride my bike. How far is it to work? \n" ); document.write( "
Algebra.Com's Answer #501957 by josgarithmetic(39627)\"\" \"About 
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Unknown variables are the time t, for walking and the distance to work, d.
\n" ); document.write( "Use the simple travel rate equation, R*T=D. Do not worry about the ratio of walking to cycling speeds.\r
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\n" ); document.write( "\n" ); document.write( "______________speed________time(hours)_______distance
\n" ); document.write( "WALK____________4____________t_______________d
\n" ); document.write( "CYCLE___________12__________t-1/6____________d\r
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\n" ); document.write( "\n" ); document.write( "Walking: \"4t=d\"
\n" ); document.write( "Cycling: \"12%28t-1%2F6%29=d\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify and try to use in the form of At+Bd=C.
\n" ); document.write( "-
\n" ); document.write( "Walk equation is like \"4t-d=0\";
\n" ); document.write( "-
\n" ); document.write( "Cycle equation, \"12t-2=d\"
\n" ); document.write( "\"12t-d-2=0\"
\n" ); document.write( "\"12t-d=2\"\r
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\n" ); document.write( "\n" ); document.write( "System is now useful as:
\n" ); document.write( "\"highlight_green%2812t-d=2%29\" and \"highlight_green%284t-d=0%29\"
\n" ); document.write( "Use Elimination Method. Subtract the second equation from the first, according to the system as just shown:
\n" ); document.write( "\"12t-d-%284t-d%29=2-0\"
\n" ); document.write( "\"12t-d-4t%2Bd=2\"
\n" ); document.write( "\"12t-4t=2\"
\n" ); document.write( "\"6t-2t=1\"
\n" ); document.write( "\"4t=1\"
\n" ); document.write( "\"highlight%28t=1%2F4%29\"------A part of the answer resutl.
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\n" ); document.write( "Now find the distance. Use the simpler original equation for WALKING.
\n" ); document.write( "\"4t=d\"
\n" ); document.write( "\"4%281%2F4%29=d\"
\n" ); document.write( "\"1=d\"
\n" ); document.write( "\"highlight%28d=1%29\" mile distance to work.
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