document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=832246>Question 832246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A hemispherical wash basin has an internal diameter of 22 cm. The basin has a uniform thickness of 10 cm. What is the area of the inner and outer surfaces of the wash basin? Answer in square centimetres correct to four significant figures.\r<BR>\n" );
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document.write( "Please show working out </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501944 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501944\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The curved surface area of a hemisphere is given by the formula<BR>\n" );
document.write( "SA = 2*pi*r^2<BR>\n" );
document.write( "The radius of the inner surface is 22/2 = 11, so<BR>\n" );
document.write( "SA of inner surface = 2*pi*11^2 = 760.26542216872996370796 = 760.2654 square cm<BR>\n" );
document.write( "The radius of the outer surface is 11 + 10 = 21<BR>\n" );
document.write( "SA of the outer surface = 2*pi*21^2 = 2770.88472046619763632405 = 2770.8847 square cm<BR>\n" );
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