document.write( "Question 70361:  The inventor of a new product believes that the cost of producing the product is given by the function: C(x)= 1.75x + 7000\r
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document.write( "The cost of 2000 units of her invention is $10,500.\r
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document.write( "If the inventor charges $4 per unit, then her profit for producing and selling x units is given by the function: P(x)= 2.25x - 7000\r
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document.write( "(a) What is her profit if she sells 2000 units?
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document.write( "(b) What is her profit if she sells 5000 units?
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document.write( "(c) What is the break-even point for sales? \n" );
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| Algebra.Com's Answer #50192 by bucky(2189)      You can put this solution on YOUR website! From the way this problem is worded, the equation for C(x) is not needed to answer the questions \n" ); document.write( "that are asked. The only equation that applies is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The first question ... What is the profit if she sells 2000 units? Calculate the profit by \n" ); document.write( "setting x equal to 2000 units so that the equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The negative sign tells you that overall she loses $2500 if she sells only 2000 units. \n" ); document.write( ". \n" ); document.write( "The second question ... What is the profit if she sells 5000 units? Do the same calculation \n" ); document.write( "as above, but this time set x equal to 5000 units so that the equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The positive answer tells you that overall she makes $4,250 if she sells 5000 units. \n" ); document.write( ". \n" ); document.write( "So somewhere between sales of 2000 units (a loss) and selling 5000 units (a gain) she \n" ); document.write( "reach a break-even point. At that break-even point her profit would be zero (neither a \n" ); document.write( "loss nor a gain). So this time set the profit equal to zero in the equation and solve the \n" ); document.write( "resulting equation for x. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Add 7000 to both sides and transpose the equation: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Divide both sides by 2.25 to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This result tells you that if she sells less than this amount she loses money, but if \n" ); document.write( "she sells more than this number of units she makes money. Therefore, you can say that \n" ); document.write( "she loses a very small amount of money if she sells 3111 units, and she makes a very small \n" ); document.write( "amount of money if she sells 3112 units. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to see your way through the problem ... especially with regarding \n" ); document.write( "the information on the costs involved with production, C(x), and the sales price of $4.00 \n" ); document.write( "per unit. That information was not needed because you were provided with an \n" ); document.write( "equation that \n" ); document.write( "directly calculates profit based on the number of units sold. \n" ); document.write( " |