document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=832173>Question 832173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a tank is filled by 6 pipes with uniforms flow in one hour.In which time 4 pipes can filled the tank at same flow? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501892 by </B><A HREF=/tutors/aboutme.mpl?userid=jean14><B>jean14(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jean14><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jean14><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We use inverse proportion.(the more pipes use the less time use to fill tanks and vise versa.)<BR>\n" );
document.write( "Step 1. Write down the ratio in types of term.( no. Of pipes and time/hour)\r<BR>\n" );
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document.write( "no. Of pipes             time (hr)<BR>\n" );
document.write( "   6                                  1<BR>\n" );
document.write( "    4                                  x<BR>\n" );
document.write( "Step 2.  Invert one of the ratios. (flip it upside down. Then multiply, divide and solve.\r<BR>\n" );
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document.write( "4/6 = 1/x   cross multiply<BR>\n" );
document.write( "4x = 6   divide both terms by 4 to get the value of x<BR>\n" );
document.write( "x = 6/4 or 1 1/2 hr   \r<BR>\n" );
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document.write( "Threfore, it will took 1 1/2 hrs for the 4 pipes to fill the tank w/ same flow </SPAN>\n" );
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