document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=832181>Question 832181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a right triangle, the bisector of the right triangle divides the hypotenus in the ratio 3:5. determine the measures of the acute angles of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501889 by </B><A HREF=/tutors/aboutme.mpl?userid=jean14><B>jean14(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jean14><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jean14><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501889\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> note: right triangle measures 90 deg.<BR>\n" );
document.write( "          Acute  angle measures less than 90 deg.\r<BR>\n" );
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document.write( "hypotenuse divided in ratio 3:5.<BR>\n" );
document.write( "This means 3 parts : 5 parts<BR>\n" );
document.write( " Add the parts 3 +5 = 8 parts. <BR>\n" );
document.write( "So, a hypotenuse has 8 parts. lets find the measure in one part.\r<BR>\n" );
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document.write( "Right tri. 90° / 8parts = 11.25° is 1 part .\r<BR>\n" );
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document.write( "Solve:<BR>\n" );
document.write( "3 : 5<BR>\n" );
document.write( "3 * 11.25  :   5 * 11.25<BR>\n" );
document.write( "33.75°  :    56.25°    final answer\r<BR>\n" );
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document.write( "Those measurements are acute angles bec. They are less than 90°.\r<BR>\n" );
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document.write( "Check: add the acute angles together<BR>\n" );
document.write( "33.75° + 56.25° = 90°<BR>\n" );
document.write( " </SPAN>\n" );
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