document.write( "Question 832093: an airplane flying against the wind travels 140 miles in the same amount of time it would take the same plane to travel 160 miles with the wind. if the wind speed is a constant 20 miles per hour, what is the speed of the plane in still air \n" ); document.write( "
Algebra.Com's Answer #501849 by mananth(16946)\"\" \"About 
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Plane speed x mph
\n" ); document.write( "wind speed 20 mph
\n" ); document.write( "
\n" ); document.write( "against wind x - 20 mph
\n" ); document.write( "with wind x + 20 mph
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\n" ); document.write( "Distance against wind 140
\n" ); document.write( "Distance with wind 160
\n" ); document.write( "Time = same equate the time against with time with current
\n" ); document.write( "t=d/r
\n" ); document.write( "140 /(x- 20 )= 160 /(x+ 20 )
\n" ); document.write( "140 *(x+ 20 )= 160 *(x- 20 )
\n" ); document.write( "140 x + 2800 = 160 x -3200
\n" ); document.write( "140 x -160 x = -3200 + -2800
\n" ); document.write( "-20 x = -6000
\n" ); document.write( "/ -20
\n" ); document.write( " x= 300 mph
\n" ); document.write( "m.ananth@hotmail.ca
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