document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=832015>Question 832015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the line that passes through the point (4,2) and is perpendicular to the line 4x+3y=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501805 by </B><A HREF=/tutors/aboutme.mpl?userid=erica65404><B>erica65404(394)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=erica65404><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=erica65404><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first you need to do, is find the slope of the given line.  Solve the equation for y.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x%2B3y=0 ALIGN=MIDDLE  ALT=\"4x%2B3y=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3y=-4x ALIGN=MIDDLE  ALT=\"3y=-4x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%28-4%2F3%29x ALIGN=MIDDLE  ALT=\"y=%28-4%2F3%29x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "the slope for this line is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-4%2F3 ALIGN=MIDDLE  ALT=\"-4%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now we need to find a slope that is perpendicular.  Take the recriprocal and multiply it by -1.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-4%2F3 ALIGN=MIDDLE  ALT=\"-4%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >'s reciprocal is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2F4 ALIGN=MIDDLE  ALT=\"-3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > and multiply it by -1 to get a slope of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F4 ALIGN=MIDDLE  ALT=\"3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Now we have <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%283%2F4%29x%2Bb ALIGN=MIDDLE  ALT=\"y=%283%2F4%29x%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" > as the beginning of the perpendicular line.  We still need to find b.<BR>\n" );
document.write( "They give you the point (4,2), plug in the x and y values into the equation and solve for b.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2=%283%2F4%29%284%2F1%29+%2B+b ALIGN=MIDDLE  ALT=\"2=%283%2F4%29%284%2F1%29+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2+=+3+%2B+b ALIGN=MIDDLE  ALT=\"2+=+3+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1=b ALIGN=MIDDLE  ALT=\"-1=b\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "now the final equation is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%283%2F4%29x-1 ALIGN=MIDDLE  ALT=\"y=%283%2F4%29x-1\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "If you would like more help, email me at ericahigley@yahoo.com. </SPAN>\n" );
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